On Sat, 19 Jan 2002, Chris Payne wrote: > Hi there, > > I made some of the changes you said below, and when I check the query I get > this: > > The query is SELECT distinct description, email, url, country, category, > type, rating from search6 WHERE description LIKE '%word%'AND category = > 'Automotive' AND country = 'Austria' AND type = 'Car Rental' ORDER BY > description > > > so to me it doesn't appear to be putting the array item in there, or am I > wrong? I am confused, thanks for your help. > > > You should probably be using: > > > > $sql .= " description LIKE '%word%' OR "; # note the spaces
Missed this error the first time round. It should be: $sql .= " description LIKE '%$word%' OR "; # note the $!! hth -- Jason Wong -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
