why not
if (!($1%2))
{
echo "even!";
}
else
{
echo "odd!";
}
Adam
On Thu, 26 Sep 2002, Brad Bonkoski wrote:
> oops...
>
> I meant:
> (if $i is odd)
> ...
>
> because $i would be the current index in the array.
>
>
> Brad Bonkoski wrote:
>
> > why not this?
> >
> > $result = mysql_query("Select * from table');
> > $num_rows = mysql_num_rows($rows);
> >
> > for ($i=0; $i<$num_rows, $i++)
> > {
> > $row = mysql_fetch_array($result);
> > if ($num_rows is odd)
> > {
> > print $row with BG color of red;
> > }
> > else
> > {
> > printf $row with BG color of purple;
> > }
> > }
> >
> > HTH
> > -Brad
> >
> > Patrick Lebon wrote:
> >
> > > Is there a mysql or array variable for the current row of a query array?
> > > I want to alternate background colours for each row of the query output so i
> > > need to know the current row number.
> > >
> > > Thanks
> > >
> > > --
> > > PHP Database Mailing List (http://www.php.net/)
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> >
> > --
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>
>
>
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