Ok...
This is the code I have setup:
for ($i=0;$i<sizeof($order_index);$i++) {
if ($delete[$i] == 1) {
print_r($order_index[$i]);
$str = implode(",",$order_index[$i]);
echo $str;
}
}
Now..upon the print_r.. The values that ARE there look like 2627
(which is order_index 26 and 27).
Basically I am trying to get the 2627 into a string that looks like:
$str = "26,27"; so I can use it in something else.
*shrugs*
I think I wma way off base here *eyes blurry* heeh
Aaron
> -----Original Message-----
> From: Rasmus Lerdorf [mailto:rasmus@;php.net]
> Sent: Wednesday, November 06, 2002 2:16 PM
> To: Aaron Wolski
> Cc: [EMAIL PROTECTED]
> Subject: Re: [PHP-DB] Imploding an array?
>
>
> You sure you want [$i] on that? Is it a 2-dimensional array?
>
> On Wed, 6 Nov 2002, Aaron Wolski wrote:
>
> > Hey all,
> >
> > Can't seem to figure out why this won't work:
> >
> > $test = implode(",", $order_index[$i]);
> >
> > When I print_r() the variable I have values so I know that works.
> >
> > Any thoughts on this?
> >
> > Thanks.
> >
> > Aaron
> >
>
>
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