Putting an & sign in front of the $id in the first line should do the trick:
$variable = &$id; A short example: $bar = 0; $foo = &$bar; $bar = 2; print $foo; //prints 2 ______________________ Marcus Rasmussen [EMAIL PROTECTED] www.marcusr.dk ------------------------------------------------------------- On 31-03-2003 at 19:56 Sebastian wrote: ------------------------------------------------------------- hello all, $variable = $id; // some other stuff.... @mysql_query here.... $id = mysql_insert_id(); to the question: How do I get $id from insert_id() to pass to $variable above? Hard to explain the situation i am in, but the query has to be below $variable, is it possible to 'globalize' $id so it passes to the top $variable? first time i ever ran into this problem. Thanks in advanced. cheers, - Sebastian -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
