On Tuesday 01 April 2003 11:59, Sebastian wrote:
> Hmm, interesting.. i dunno why it doesn't work for me, here is a bit of the
> code, $var isn't getting the output of $id, any ideas?
Are you sure that $id contains what you think it contains?
Also could you explain the reason why your code is laid out the way it is?
Line 1
> $var = &$id;
Line 2
> if( ! $forg = resizer_main("image","image_$var", blah, blah........");
Line 3
> $org = getimagesize( "$root/$forg" );
Line 4
> $result = @mysql_query("INSERT INTO images blah blah.....");
Line 5
> $id = mysql_insert_id();
In Line 2, $var will contain whatever $id contained in Line 1. IOW if the
value of $id was not defined before Line 1, then $var will be similarly
"undefined". Is that your intention?
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