Add some debugging code. Are you sure 36 and 37 end up in the $array_id
array? Try printing out $_POST['idlist'] and $thisid as you loop through
this thing to figure out where/what is getting skipped.
Ditto the idea on doing this another, way, btw... :)
---John Holmes...
----- Original Message -----
From: "Dillon, John" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, May 29, 2003 11:44 AM
Subject: [PHP] Getting POSTed values from dynamically named checkboxes
My problem relates to IF statement in the following code. There are two
checkboxes, named altid$thisid, so for instance they become altid36 and
altid37. When the form is submitted with both checked, I can read the first
altid36, but the second does not pass the IF test. Any suggestions re
possible reasons?
$checkedalts = array();
$x=0;
$y=1;
$array_id = explode(",", $_POST["idlist"]);
foreach($array_id as $thisid){
if(${"altid" . $thisid} == 1){
//OR if(ISSET($_POST["${"altid" . $thisid}"])){
$checkedalts[$x] = $thisid;
$checkedalts[$y] = ${"altprice" . $thisid};
$x=$x+2;
$y=$x+1;
}
}
The HTML before submission is (without the <!--):
<!--
<tr>
<td>Whatever</td>
<td><input type="checkbox" name="altid36" value="1"
></td>
<td class=textset22><input size="10" type=textfield
value="" name="altprice36"></td>
</tr><tr>
<td>Something else</td>
<td><input type="checkbox" name="altid37" value="1"
></td>
<td><input size="10" type=textfield value=""
name="altprice37"></td>
</tr><tr>
//-->
Thanks,
John
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