Oh wait.. unless that output is required somehow. I removed the echo
statement now my request isn't being replied to by the database script.
Seems I desparately need a lesson in socket connections. Does anyone know
of a good book or tutorial other than the manual that goes into this stuff
in depth?
- Kevin
----- Original Message -----
From: "Kevin Stone" <[EMAIL PROTECTED]>
To: "Kevin Stone" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Monday, June 16, 2003 2:54 PM
Subject: Re: [PHP] How to avoid Socket Post output?
> ACK! NEVER MIND!
>
> I'm just blind. I didn't see the echo statement on the fgets() line.
>
> Problem solved.
>
> - Kevin
>
> ----- Original Message -----
> From: "Kevin Stone" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Monday, June 16, 2003 2:46 PM
> Subject: [PHP] How to avoid Socket Post output?
>
>
> > Hello list,
> >
> > I'm attempting to use the PostToHost() function to send a request to a
> > remote script. The purpose for this is to request and retrieve
> information
> > from a remote database without the need for messy HTTP & HTML methods.
I
> > realize that I could use an HTML form, put the data in hidden fields,
and
> > send the request that way, but then I would have to redirect back from
the
> > master script recording an unwanted page in the 'Back Button' history.
> I'd
> > like to avoid that so I'm investigating methods of POST'ing through a
> manual
> > socket connection.
> >
> > Here is that PostToHost() function..
> >
> > /*********************************************************
> > PostToHost($host, $path, $data_to_send)
> > $host; valid domain (ie. www.domain.com)
> > $path; relative URL (ie. /myfile.php)
> > $data_to_send; urlencoded key/val string (ie.
> > "key=val&key2=val2&key3=val3")
> > *********************************************************/
> > function PostToHost($host, $path, $data_to_send)
> > {
> > ob_end_flush();
> > $fp = fsockopen($host,80);
> > fputs($fp, "POST $path HTTP/1.0\n");
> > fputs($fp, "Host: $host\n");
> > fputs($fp, "Content-type: application/x-www-form-urlencoded\n");
> > fputs($fp, "Content-length: " . strlen($data_to_send) . "\n");
> > fputs($fp, "Connection: close\n\n");
> > fputs($fp, $data_to_send);
> > while(!feof($fp))
> > {
> > echo fgets($fp, 128);
> > }
> > fclose($fp);
> > }
> >
> >
> > It works great! The only problem is I get output from the socket
> connection
> > and I don't know how to skip over it...
> >
> > HTTP/1.1 200 OK
> > Date: Mon, 16 Jun 2003 20:10:36 GMT
> > Server: Apache/1.3.20 (Unix) ApacheJServ/1.1.2 PHP/4.2.3
> > FrontPage/5.0.2.2510 Rewrit/1.1a
> > X-Powered-By: PHP/4.2.3
> > Connection: close
> > Content-Type: text/html
> >
> > I'm very much a newbie to all of this so you'll have to forgive me. But
> I'm
> > wondering if there is anyway to avoid this output and have a completely
> > invisible manual socket POST?
> >
> >
> > Thanks,
> > Kevin Stone
> > [EMAIL PROTECTED]
> >
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
> >
>
>
>
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