----- Original Message ----- From: "David Nicholson" <[EMAIL PROTECTED]> To: "Kevin Stone" <[EMAIL PROTECTED]> Cc: <[EMAIL PROTECTED]> Sent: Monday, June 16, 2003 3:22 PM Subject: Re: [PHP] How to avoid Socket Post output?
> Hello, > > > This is a reply to an e-mail that you wrote on Mon, 16 Jun 2003 at 22:00, > lines prefixed by '>' were originally written by you. > > > Oh wait.. unless that output is required somehow. I removed the echo > > statement now my request isn't being replied to by the database > > script. > > For a quick fix, change: > echo fgets($fp, 128); > to: > fgets($fp, 128); > > All the best, > > David. Yes but when I fail to output the socket file the request is no longer recieved. No data is recorded in the POST array. Let me explain once more what I'm doing.. 1) Initiate Script-A through the browser. 2) Script-A opens a socket connection to Script-B and posts a request. 3) Script-B produces a formated data string based on the requst. 4) Script-B then opens a socket connection to Script-A and posts the data. It should be seamless and it works for the most part. But the thing is it outputs this generic server info which you can see in this working example.. http://www.helpelf.com/test.php You'll notice in the example that this server info.. I don't know what it is becuase this is the first time I've done anything like this.. gets outputed along with the request. I can't NOT (double negative) output the request file becuase it contains the headers and data which make it all work. At least that is what I realized a few minutes ago when I said ACK then Oh (see two posts below). :-) Now I'm looking for a way to avoid that server info output, without compromizing the functionality of the method, if it is possible to do so. - Kevin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
