function DisplayLinks($links,$names) { $namecount = sizeof($names); for($a=0;$a<$namecount;$a++) { $name = $names[$a]; $url = $links[$a]; echo ":::<a href= '$url''>$name</a>:::\n";
} //End for } // End DisplayLinks function try this and assigning the names you want to be displayed to the names array and links to the links array... I know this isnt pretty but it should work ----- Original Message ----- From: "Daniel J. Rychlik" <[EMAIL PROTECTED]> To: "Chris Sherwood" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> Sent: Wednesday, June 25, 2003 12:59 PM Subject: Re: [PHP] Passing Array to object > I remember seeing somewhere that you could only pass a single deminsional > Array to a class. But I cant even get this one deminsional to work. If I > place the links inside the main class and call it an attribute it works > fine. > > var $newlinks = array (...)' > > When I var_dump($myarray) I recieve the output as expected. For some > reason its still giving me the warning. hmmm...... Ive tried everything > that was suggested. I think I need to go back and take another look at OO > programming in php. > > > ----- Original Message ----- > From: "Chris Sherwood" <[EMAIL PROTECTED]> > To: "Daniel J. Rychlik" <[EMAIL PROTECTED]>; > <[EMAIL PROTECTED]> > Sent: Wednesday, June 25, 2003 1:46 PM > Subject: Re: [PHP] Passing Array to object > > > > hmmm okay > > cause list works by assigning elements in order from an array > > each iterates thru each element in a list so you want to pass both > elements > > at the same time so you need to pass an array to get the effect your > looking > > for > > > > ie $name being from the first array element, and $url being from the > second > > array element... > > > > so I am thinking you wish to assign urls and names to a single array you > > will want to make it a multidimensional array > > ie array (array(name, link),array(name,link)) > > > > hope this helps you daniel > > > > ----- Original Message ----- > > From: "Daniel J. Rychlik" <[EMAIL PROTECTED]> > > To: "Daniel J. Rychlik" <[EMAIL PROTECTED]>; "Chris Sherwood" > > <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> > > Sent: Wednesday, June 25, 2003 11:17 AM > > Subject: Re: [PHP] Passing Array to object > > > > > > > Its erroring at my display links function. This function is inside my > > main > > > class. > > > > > > function DisplayLinks($links) { > > > > > > while(list($name, $url) = each($links) { > > > > > > echo ":::<a href= '$url''>$name</a>:::\n"; > > > > > > } //End while > > > > > > } // End DisplayLinks function > > > > > > > > > I dont see why it wont work... I even try assigning $links to the > array. > > > > > > > > > ----- Original Message ----- > > > From: "Daniel J. Rychlik" <[EMAIL PROTECTED]> > > > To: "Chris Sherwood" <[EMAIL PROTECTED]>; > > > <[EMAIL PROTECTED]> > > > Sent: Wednesday, June 25, 2003 1:08 PM > > > Subject: Re: [PHP] Passing Array to object > > > > > > > > > > yea, I gave that a shot, Same message. Logically it makes sense, but > php > > > > doesnt like it. > > > > > > > > by the way, thanks for your help Chris. You've helped me in the past. > > > > -Daniel > > > > > > > > ----- Original Message ----- > > > > From: "Chris Sherwood" <[EMAIL PROTECTED]> > > > > To: "Daniel J. Rychlik" <[EMAIL PROTECTED]>; > > > > <[EMAIL PROTECTED]> > > > > Sent: Wednesday, June 25, 2003 1:02 PM > > > > Subject: Re: [PHP] Passing Array to object > > > > > > > > > > > > > Have you tried to assign the array to a variable then pass the > > variable > > > to > > > > > the function ie > > > > > > > > > > $index = new main(); > > > > > $yourvar = array('array values'); > > > > > > > > > > > > > > > $index->SetLink ($yourvar); > > > > > > > > > > ----- Original Message ----- > > > > > From: "Daniel J. Rychlik" <[EMAIL PROTECTED]> > > > > > To: <[EMAIL PROTECTED]> > > > > > Sent: Wednesday, June 25, 2003 10:46 AM > > > > > Subject: [PHP] Passing Array to object > > > > > > > > > > > > > > > Hello, > > > > > > > > > > I am developing a site that uses classes to reuse code and objects. > > > > > > > > > > I have in my main class a > > > > > > > > > > function SetLinks($newlinks) { > > > > > > > > > > $this->links = $newlinks; > > > > > > > > > > } > > > > > > > > > > And another function that displays them in the same class main { > > > > > > > > > > > > > > > I have another file called index.php that basically just passes > > > attributes > > > > > to the main class and the main class displays them. > > > > > > > > > > Im having a bit of trouble passing an array to the object > > > > > > > > > > in the index.php > > > > > > > > > > I create new. > > > > > > > > > > $index = new main(); > > > > > $index->SetLink = array ( 'Link1' => 'link1.php', > > > > > ..... ); > > > > > > > > > > When I run I recieve "Variable passed to each() is not an array or > > > object > > > > " > > > > > > > > > > so I tried this > > > > > > > > > > $index->SetLink($newlink = array('link1' => ...); > > > > > > > > > > same error message. I was wondering if someone could shed some > light > > on > > > > > what Im doing wrong. > > > > > > > > > > Thanks > > > > > Daniel > > > > > > > > > > > > > > > > > -- > > > > PHP General Mailing List (http://www.php.net/) > > > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > > > > > > > > -- > > > PHP General Mailing List (http://www.php.net/) > > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > > > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php