James,
My question had more to do with why the authors would give this usage when
array_push is not documented to behave so (as you correctly described).
Were they describing an earlier version of array_push? A simple buggy
example? A typo perhaps?
Since the authors Hughes and Zmievski are big names in PHP, though mortals
like you and me, I'm inclined to think they were thinking about something.
----- Original Message -----
From: "Jason Wong" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Sunday, August 03, 2003 1:27 AM
Subject: Re: [PHP] Pushing array onto array
> On Sunday 03 August 2003 13:02, Hank TT wrote:
> > Well, I might have been more specific about their example, since not
> > everyone has the book. An excerpt below (so I don't need to retype all
the
> > names of characters and foul creatures from the Lord of the Rings):
> >
> > ---------------------------
> > $arr1 = array('G', 'R', 'Sr');
> > $arr2 = array('N', 'Su', 'O');
> >
> > $arr3 = array_push($arr1, $arr2);
> >
> > print $arr3[3][1];
> > //prints Su
> > ---------------------------
>
> I don't see how your example could work. array_push() does NOT return an
> array. The results of array_push() is placed in the first argument -- in
this
> case $arr1.
>
> > Weird usage....
>
> Think of it like this -- it adds the 2nd array onto the 1st array.
>
> It does NOT add the *contents* of the 2nd array to the 1st array -- for
that
> you would probably use array_merge().
>
> Do a print_r($arr1), it might help you visualise what happens.
>
> --
> Jason Wong -> Gremlins Associates -> www.gremlins.biz
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development *
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