For the images that don't contain "http://"; my program is already able to get them from the web server. In other cases, I have to determine the name of the directory where the html page is located. Thus, the equivocal paths are the problem, for example:
www.php.net/manual/it/index.php www.php.net/manual/it/ www.php.net/manual/it The reply of the server web is the same in the three cases. The input of the my program could be any paths between the mentioned ones. I need to poll out the path www.php.net/manual/it/ Best regards. Andrea ----- Original Message ----- From: "Ryan Gibson" <[EMAIL PROTECTED]> To: "Andrea Tricco" <[EMAIL PROTECTED]>; "php-general" <[EMAIL PROTECTED]> Sent: Friday, September 12, 2003 12:26 PM Subject: Re: [PHP] caching program > You could pull out all the img src attributes and if they don't contain > "http://"; then prepeand the address of te page then download otherwise just > downlocad the url, but to get the page to work in the new location you may > have to replace the img src attributes > > Ryan Gibson > ----------- > [EMAIL PROTECTED] > > On 17/9/03 11:16 am, "Andrea Tricco" <[EMAIL PROTECTED]> wrote: > > > Hi, > > I'm using the function "file_get_contents()" to replicate the content of a > > remote html page on my server. > > But, the function file_get_contents() works even when the name of the file > > is not specified. For example: > > > > "http://www.php.net"; rather that "http://php.net/index.php"; > > > > Does a method exist to know the name of the file received form web server? > > > > I would like to write a program that automatically downloads the images > > inserted into a html page. > > For this reason, I need to determine the paths of the images in order to get > > them from the web server. > > In other words, my program should work as the "Save as" function (File menu) > > of any Web browser. > > > > Can anybody help me? > > > > Best regards. > > Andrea > > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
