On 17 March 2004 17:09, Chris W. Parker wrote: > > $var++ is a post incrementer meaning the value is updated at the next > command*.
> * i'm not exactly sure how the compiler determines when to post > increment, but i think i'm correct. Not quite -- the increment is performed immediately after the access -- in fact, as part of the same operation. So: $x = 3; $y = ($x++ * 2) + $x; is likely to give you $y==10, not 9. (I say "is likely to", because you don't have any absolute cast-iron guarantees that a compiler won't, if it thinks it has good reason, commute the above to $x + ($x++ * 2), which would give you $y==9! In general, it's best to regard the value of a pre- or post-incremented variable as uncertain in the rest of the expression containing it.) Cheers! Mike --------------------------------------------------------------------- Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php