hello all
i've a problem, serious one.
how can i pass the name of a file upload to a function ?
i need to do the upload of 1 file, but want to use a function, so that the main file stays small
the problem is, when passing the file name, throw the $_FILES super global , is not recognized in the function...
here is the code:
############ the function (or part of it)
function uploadfile ($userfile, $name2file,$uploadir) {
//userfile is where file went on webserver
echo 'inside'; <<< ---- debuging purpose
$userfile = $_FILES['userfile']['tmp_name']; //userfile_name is original file name
$userfile_name = $_FILES['userfile']['name'];echo 'User File name: '.$userfile_name; <<< --- debuging purpose
############## main program ##################33
uploadfile ($_FILES['user_picture'],$_SESSION['valid_user'].'_picture',$USERPICS);
this is the call to the function above
the problem is that inside the function, the file name is not recognized... when i try to print the filename, is empty ....
any ideas ????
it only works if $_FILSE['user_picture'] is $userfile ......
should i pass the values by reference ?i mean, putting some sort of & ??
cheers and best regars
Bruno
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