I tried removing the zeros, but, I get the same result:
$id = 000011;
$id = ltrim($id, '0');
echo $id; // Displays: 9 instead of 11 ???
This didn't work either:
$id = 000011;
settype($id, 'string');
$id = ltrim($id, '0');
echo $id; // Displays: 9 instead of 11 ???
No matter what I do, $id=000011 is seen as "9". Only way is to pass the
number without the zeros ($id=11), but, because this data is being read from
a database, I can't change the format because PHP seems to be converting it
immediately to a 9 instead of reading it as 11 or even 000011.
If PHP sees this as an octal, then why does gettype(000011) = INTEGER? This
makes no sense.
Monty.
> From: [EMAIL PROTECTED] (Jay Blanchard)
> Newsgroups: php.general
> Date: Fri, 2 Apr 2004 15:38:03 -0600
> To: "Monty" <[EMAIL PROTECTED]>, <[EMAIL PROTECTED]>
> Subject: RE: [PHP] Strange Numeric Conversion...
>
> [snip]
> Why is this happening???
>
> $id = 000011;
> echo $id; // Displays: 9
>
> $id = 11;
> echo $id; // Displays: 11
>
> How do I make the first number (00011) display as 11? Why is it showing
> 9?
> [/snip]
>
> First of all you have "naked" numbers. The first one, 000011, looks like
> a binary number (which actually should be 3). You are going to have to
> trim the leading zero's from the number to have it display as 11.
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