Allmost, after having a quick look at the source i tell you they
do it like that:
<div id="loading" style="display:block">
... loading stuff here ...
</div>
.... page loading here ....
done?
JS: document.getElementByid('loading').display='none';
take a look for yourself :-)
James Harrell wrote:
Hi Rene,
Here's a thought- make your animated gif that's a "grow-bar"
that fills from left to right. Maybe it maxes out at 99% or
loops back around to 0 after reaching 100. :) Display this at
the top of the screen - but not within a table that is part of
the results display. More on why shortly.
Send about 256 characters of HTML (including the IMG SRC link
to your gif), then issue a flush(). At this point begin your
long-running query, displaying output as it becomes avialable.
Once the output is complete, issue a javascript that changes
the gif to a different one that's not animated (ex: 100%).
A few things to keep in mind:
- Some IE browsers won't display anything until 255 chars
have been output- hence the 256 number above.
- Some NS browsers won't display a portion of a table until
the entire table including closing tag has been written.
Hence, don't put your grow-bar inside a table unless it's
completed before issuing the long-running query.
Hope this helps,
james
-----Original Message-----
From: René Fournier [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 09, 2004 3:35 PM
To: php
Subject: [PHP] Expedia.com
When Expedia.com is searching for flights, it displays a page with a
little animated GIF progress bar, then display the results.
How do they do that? How does the page sit idle until the query is
finished, and then sends a new page with the results? I was thinking
that they might use HTTP-REFRESH or something, and just keep hitting
the database until the result is there. But is there a "best way" to do
this? In my application, when the user clicks a certain button, it will
take 10-20 seconds for the operation to complete—during that time I
need the web browser to "waiit" for the data.
I looked around for an article on this, but I'm not sure how to
characterize this operation.
...Rene
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