On Thursday 10 June 2004 18:58, Phil Ewington - 43 Plc wrote: > Can anyone tell me how to pass arguments to a PHP script from the command > line? I know I need to use the -args option but how exactly, I have tried > the following...
manual > Using PHP from the command line > /usr/bin/php myscript.php -args key=value > > but this does not work, the script executes but key is not available as > $_GET["key"] in my script. Any pointers will be much appreciated. print_r($argv); -- Jason Wong -> Gremlins Associates -> www.gremlins.biz Open Source Software Systems Integrators * Web Design & Hosting * Internet & Intranet Applications Development * ------------------------------------------ Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general ------------------------------------------ /* An American's a person who isn't afraid to criticize the president but is always polite to traffic cops. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
