Phil Ewington - 43 Plc wrote on donderdag 10 juni 2004 15:11:
>> Phil Ewington - 43 Plc wrote on donderdag 10 juni 2004 14:27:
>>
>>>> Phil Ewington - 43 Plc wrote on donderdag 10 juni 2004 12:58:
>>>>
>>>>> Hi All,
>>>>>
>>>>> Can anyone tell me how to pass arguments to a PHP script from the
>>>>> command line? I know I need to use the -args option but how
>>>>> exactly, I have tried the following...
>>>>>
>>>>> /usr/bin/php myscript.php -args key=value
>>>>
>>>> You don't have to call the -args argument. just run the script
>>>> from command line like this:
>>>>
>>>> php myscript.php value
>>>>
>>>> Where value is the argument you want to use in the script.
>>>> These arguments are stored in an arrray ($argv).
>>>>
>>>> Do a print_r($argv) and you can see the content.
>>>
>>> OK, but if no param name is passed in, I assume that the order they
>>> are passed in as must be correct or the script will not know what
>>> values belong to which parameters? This seems a little odd, I assume
>>> that $argv only exists when accessed from the command line? My
>>> script needs to be excuted from both command line and from web
>>> browsers.
>>>
>>
>> How do you mean the order must be correct. Use some code like this
>> to give it an index value. for ($counter=0; $counter < $argc;
>> $counter++) { list($key, $value) = each($argv);
>> echo ("key ". $key . "has value : " . $value . "\n");
>> }
>
> Your example was...
>
> php myscript.php value
>
> That is just a value, no parameter name as with a query string, take
> this example...
>
> php myscript.php a b
>
> Let's say that this was requested from a browser like
> myscript.php?1=a&2=b
>
> PHP uses 1 & 2 to refer to the values, but the values would get mixed
> up if I was to use...
>
> $argv[0] & $argv[1]
>
> and the order of a and b were different when the script was called.
> Does that make sense? I find it odd that I need to write more code to
> 1) check $_GET and 2) check $argv, also simple error checking will
> fail for command line stuff when checking that all the required
> params are present.
>
>
ic now i understand what you mean :)
Why not just pass the arguments on commandline like this:
php myscript.php 1=a 2=b
and then just split on '=' to get key & value.
>>> From what i understand the argv & argc are only avaliable when the
>> script is run from commandline. Just do a check on this and if not
>> there get some $_POST or $_GET variables.
>>
>>>>
>>>>>
>>>>> but this does not work, the script executes but key is not
>>>>> available as $_GET["key"] in my script. Any pointers will be much
>>>>> appreciated.
>>>>>
>>>>> TIA
>>>>>
>>>>> Phil.
>>>>>
>>>>> ---
>>>>> Phil Ewington - Technical Director
>>>>>
>>>>> 43 Plc - Ashdale House
>>>>> 35 Broad Street, Wokingham
>>>>> Berkshire RG40 1AU
>>>>>
>>>>> T: +44 (0)1189 789 500
>>>>> F: +44 (0)1189 784 994
>>>>> E: mailto:[EMAIL PROTECTED]
>>>>> W: www.soyouthink.com
>>>>>
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