<?php
if ($recordset['field'] != "1") {
?>
<a href="#" onMouseOut="MM_swapImgRestore()"
onMouseOver="MM_swapImage('PreviousPage','','/URL/ ButtonName.gif',1)"><img
src="/URL/ButtonName.gif" alt="Previous Page" name="Previous Page"
width="150" height="20" border="0"></a>
<?php } other php code ?>
You can close out your php declaration at any time and just put in regular text. It's a lot easier doing it this way than echo'ing many lines and you don't have to worry about escaping quotes.
On Jul 23, 2004, at 2:07 PM, Robb Kerr wrote:
I've got a conditional button that needs to appear/hide on my page
depending upon the contents of a field in my database. The button is an
image and has a long URL and JavaScript for image rotation attached to it.
Needless to say, the href is quite long and includes several "'"
characters. My conditional works great but I want to know if there is an
easy way to escape the whole href so that the "'" characters will not be
seen as PHP quote marks. See below...
<?php
if ($recordset['field'] != "1") {
echo '<a href="#" onMouseOut="MM_swapImgRestore()"
onMouseOver="MM_swapImage('PreviousPage','','/URL/ ButtonName.gif',1)"><img
src="/URL/ButtonName.gif" alt="Previous Page" name="Previous Page"
width="150" height="20" border="0"></a>;
?>
Thanx in advance, Robb -- Robb Kerr Digital IGUANA Helping Digital Artists Achieve their Dreams ---------------------------------------------------- http://www.digitaliguana.com http://www.cancerreallysucks.org
-- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
-- Brent Baisley Systems Architect Landover Associates, Inc. Search & Advisory Services for Advanced Technology Environments p: 212.759.6400/800.759.0577
-- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
