From: "Geoff Caplan" <[EMAIL PROTECTED]>
Why does the non-existent key in the array below evaluate to the first char of the array value?
$foo = '' ; $foo['one']['two'] = 'test-value' ;
// Evaluates to: string(1) "t" var_dump( $foo['one']['two']['three'] ) ;
JH> Strings are arrays. PHP probably takes the string 'three' and converts it to
JH> a integer to see what "key" of the string you're requesting.
JH> $foo = 'bar'; JH> echo $foo[1]; //should echo 'a'
JH> Does that help or do you need a deeper explanation (that I probably can't
JH> provide!) ;)
I think you are probably right - but this behaviour causes problems. For example:
$foo['one']['two'] = "test-string" ;
// Evaluates to TRUE (not what's wanted!) isset( $foo['one']['two']['three'] ) ;
I need a reliable way to test for the non-existence of a multi-dimensional key. Any ideas? I guess I could convert the keys into a string via a loop and compare that, but there must be a more elegant way, surely?
How about is_array()?
if(is_array($foo['one']['two']))
{ echo 'multi dimensional array found'; }You also have is_string(), empty(), etc...
---John Holmes...
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