Yes.... but not :-).
With you use these magic functions, when you write $o->a = 'foo', you create a property in the object. Not ? Even if it is stored in an array member, __set() create a property and __get() retrieve its value.
Doc says :
>The $name parameter used is the name of the variable that should > be set or retrieved. >The __set() method's $value parameter specifies the value that > the object should set set the $name.
Conclusion :
class OO
{
private $elem = array();
public function __get ($prop)
{
if (isset($this->elem[$prop])) {
return $this->elem[$prop];
}
else
{
return NULL;
} public function __set ($prop, $val)
{
$this->elem[$prop] = $val;
}
}$o = new OO();
echo isset($o->a) ? "yes\n" : "no\n"; # Must return false and return false effectively, cool
$o->a = 'foo';
echo isset($o->a) ? "yes\n" : "no\n"; # Must return false and return false effectively, NOT COOL
Fred.
Catalin Trifu wrote:
Hi,
Is this really a bug. I think not. There is no variable $o->a or $a->b in the class OO there is only the variable $elem and $a and $b is a member of that array So ... The fact that PHP5 provides __set and __get magic functions does not mean that the actual variables exist with that particular name in the class ? Perhaps it would be nice to have a __isset magic function ?
Cheers Catalin
<?php
class OO { private $elem = array("a" => 1);
public function __get ($prop) { if (isset($this->elem[$prop])) { return $this->elem[$prop]; } else { return NULL; } }
public function __set ($prop, $val) { $this->elem[$prop] = $val; } }
$o = new OO();
echo isset($o->a) ? "yes\n" : "no\n"; echo isset($o->b) ? "yes\n" : "no\n";
echo is_null($o->a) ? "yes\n" : "no\n"; echo is_null($o->b) ? "yes\n" : "no\n";
?>
I expected something like this:
yes no no yes
But got this:
no no no yes
It looks like isset() can't handle object properties correctly. I'll post the bug on php.net.
--
Daniel Schierbeck
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