Re: [PHP] forms/variables/create database

[Minuk Choi]

try this : 

$link = mysql_connect($host, $user, $pass);
Note : No SINGLE quotes.
In PHP, quotations are as follows 

$host = 'localhost';
$a = '$host';
$b = "$host";
echo $a;
that prints $host
echo $b;
that prints localhost.
HTH
-Minuk
----- Original Message ----- 
From: "bigmark" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Sunday, October 10, 2004 10:23 PM
Subject: [PHP] forms/variables/create database


hi, does anyone know why this is not working, i have married 2 pieces of
code together and i have no idea what im doing--any help is appreciated.
I get an error that says it cant find the host--$host so obviusly its not
passing it from the form.
/////////////////////////////////////////
<?php
$host =  $_POST['host'];
$user =  $_POST['user'];
$pass =  $_POST['pass'];
$db_name =  $_POST['db-name'];
$link = mysql_connect('$host', '$user', '$pass');
if (!$link) {
  die('Could not connect: ' . mysql_error());
}
if (mysql_create_db('db_name')) {
  echo "Database created successfully\n";
} else {
  echo 'Error creating database: ' . mysql_error() . "\n";
}
?>
/////////////////////////////////////////////
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