On Sun, 17 Oct 2004 17:23:14 -0700, bruce <[EMAIL PROTECTED]> wrote:
> i have a prob/issue that i can't see.. i'm trying to geneate a page with
> multiple lists so that the user has to select an item from all 3 lists in
> order to access the next page...
>
> the 1st select/list allows the user to select either one or more items. the
> 2nd/3rd select lists require the user to select only a single item from the
> lists.
>
> ie:
> list1 list2 list3 >submitBTN<
>
> the user would select the items from all three lists, and hit the selectBTN,
> to go to the next page...
>
> the prob that i'm having is that if i simply select item(s) from the 1st
> list, then the code allows the user to continue...in other words, the app
> looks as though the user has selected an item from the 2nd/3rd even though
> they haven't been selected... in examining the code, it appears that the
> last item in the 2nd/3rd lists is being somehow read/inserted into the
> items, and are somehow included in the querystring...
>
> my code is:
>
> /*
> generate the state list
> */
> echo"
> <div style='position:absolute; top:320px; left:50px; width:400px;'>
> <form name='test' method='get' action='$foo.php'>
Why $foo here? Maybe not enough context for me to understand the
reason, I dunno.
> <div style='position:relative; top:10px; left:10px;'>
> <select multiple size=10 name='state[]'>
> ";
>
> $state_query = "select * from stateTBL";
> $res = mysqli_query($link, $state_query);
> //$res = mysql_query($query);
>
> //go ahead and process/populate the drop down
> //menu
> echo "<option value ='*'>All States</option>\n";
> while($row = mysqli_fetch_array($res, MYSQL_ASSOC))
> {
> echo "<option value
> ='".$row['val']."'>".$row['name']."</option>\n";
>
> }
>
> echo"
> </select>
> </div>
> ";
>
> /*
> generate the year list
> */
> echo"
> <div style='position:absolute; top:10px; left:240px; width:100px;'>
> <select multiple size=1 name= 'year'>
> ";
Did you mean year[] here? Otherwise why multiple?
> $year_query = "select * from yearTBL";
> $res = mysqli_query($link, $year_query);
> //$res = mysql_query($query);
>
> //go ahead and process/populate the drop down
> //menu
> while($row = mysqli_fetch_array($res, MYSQL_ASSOC))
> {
> echo "<option value
> ='".$row['year']."'>".$row['year']."</option>\n";
> }
>
> echo"
> </select>
> </div>
> ";
>
> /*
> generate the terms list
> */
> echo"
> <div style='position:absolute; top:10px; left:325px; width:100px;'>
> <select name= 'term'>
> ";
>
> $term_query = "select * from termTBL";
> $res = mysqli_query($link, $term_query);
> //$res = mysql_query($query);
>
> //go ahead and process/populate the drop down
> //menu
> while($row = mysqli_fetch_array($res, MYSQL_ASSOC))
> {
> echo "<option value ='".$row['ID']."'>".$row['term']."</option>\n";
> }
>
> echo"
> </select>
> </div>
> ";
>
> $blah = $userdata['session_id'];
>
> echo"
> <div style='position:relative; top:-150px; left:475px;'>
> <input type='submit' name='sub1' value='submit'>
> </div>
> <input type ='hidden' name='sid' value='$blah'>
> <input type='hidden' name='display' value='state'>
> </form>
> </div>
> ";
>
> in foo.php, i simply display the $_GET['state'], $_GET['year'],$_GET['term']
> vars to see what they are...
>
> if i make all the select vars for the query terms arrays, it works as it
> should, in that if all three lists aren't selected, then the user can't
> proceed. however, if i use the select <select name = 'foo'> for the 2nd/3rd
> lists, then the logic screws up...
>
> any idea why this is occuring....
>
> is there a better way/example of using multiple drop down lists within a
> single form.....
Possibly. I'd recommend using print_r($_GET) to see your form
submissions. To make sure your actually getting what you want to be
getting.
> any thoughts/comments/pointers would be helpful.. i'm pretty sure that the
> issue/prob is rather straight forward/simple, but i can't see it right
> now....
Not sure exactly what is broken, is that your entire script as posted?
--
Greg Donald
Zend Certified Engineer
http://gdconsultants.com/
http://destiney.com/
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