Hi All,
this page,
http://www.freewebmasterhelp.com/tutorials/phpmysql/5
has the below code,
<?
$i=0;
while ($i < $num) {$first=mysql_result($result,$i,"first"); $last=mysql_result($result,$i,"last"); $phone=mysql_result($result,$i,"phone"); $mobile=mysql_result($result,$i,"mobile"); $fax=mysql_result($result,$i,"fax"); $email=mysql_result($result,$i,"email"); $web=mysql_result($result,$i,"web"); ?>
<tr>
<td><font face="Arial, Helvetica, sans-serif"><? echo $first." ".$last; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><? echo $phone; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><? echo $mobile; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><? echo $fax; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><a href="mailto:<? echo $email; ?>">E-mail</a></font></td>
<td><font face="Arial, Helvetica, sans-serif"><a href="<? echo $web; ?>">Website</a></font></td>
</tr>
<? $i++; }
echo "</table>";
which I basically understand, except the html generation. I am trying to create something similiar, although, I think there are some errors in even perhaps my logic..?
<html>
<body>
<h1><center>Jumbo Status</center></h1><br>
<?php
$db = mysql_connect("localhost", "root", "grunger");
mysql_select_db("status",$db);
$result = mysql_query("SELECT ProductTypes.product_type_detail FROM ProductTypes",$db);
$myrow = mysql_fetch_array($result);
$num = mysql_num_rows($result);
?>
<table aligh="center" border="2">
<tr>
<td>Product Type</td>
</tr>
<?
$i=0;
while ($i < $num){
$product_type=mysql_result($result,$i,"product_type_detail");
echo "<tr><td><? echo $product_type ?></td></tr>"
}
$i++
?>
</table>
</body>
</html>
I get the folowing error,
*Parse error*: parse error, unexpected '}', expecting ',' or ';' in */var/www/html/products.php* on line *20
*
which is the $i++ section.
Cheers.
Mark Sargent.
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