Before anyone get's confused I thought I should note that $this won't work because I need the name of the object for use _outside_ of the class itself too. For instance I have a group of about 30 functions in a seperate file which directly modify $front_page. $front_page will now be inside of an object, and I _could_ just change them to $pge->front_page, but here's the problem. I'm doing all this so I can have variable function output. So for now I use the object name $pge to output data, but in the future I may need to use $xml or $pge_error. But I don't want to go through all the functions and change the names, so I use a variable variable. But I don't know how to get the variable variable name! So what I want is to see what name $this is holding, then declare what comes after $ as the value of a global variable which I will use in a variable variable. I know, I know, it's really complicated. But it really is the most non-constraining way of going about it, as I'm probably going to use this class many times in the future. So I'm still stumped. Am I going to have to just use a hack-around till a version of PHP includes such an odd class function, of which I know of know other such existing function in any language? :( -- Plutarck Should be working on something... ...but forgot what it was. ""Plutarck"" <[EMAIL PROTECTED]> wrote in message 9c21ks$cp$[EMAIL PROTECTED]">news:9c21ks$cp$[EMAIL PROTECTED]... > I've been using a function to output HTML to the user's browser, and now my > use has made it neccessary to put it all inside a class. > > All's going find and dandy and I've got it all working. However one of it's > variables is $front_page. > > Now in other pages there are references to $front_page, and I want to change > them to something like $objectname->front_pagee. > > The problem is that I can't know what the object will be named ahead of > time! > > So my hack-around is in the class constructor I set a global variable called > $pge with the value submitted to the constructor. So someone would do this: > > $somename = new Display(somename); > > But if someone typos the and the name of the variable is different from the > one submitted to the constructor, all the code will break! That's because > I'm using a variable variable to refer to $front_page, like this: > > ${$pge}->front_page > > I told you it was a hack-around, and it isn't a good one. > > > So is there ANY way to get the name of the object in PHP code without > knowing the name of the object ahead of time? > > I'm really stumped! > > > > -- > Plutarck > Should be working on something... > ...but forgot what it was. > > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > To contact the list administrators, e-mail: [EMAIL PROTECTED] > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
