Generally, scope is fairly loose in PHP. If $row is set by
mysql_fetch_array(...) it should carry throughout your script as it is,
unless modified. Try commenting out non-relavant pieces of the code and
var_dump(...)ing the $row variable at the start and throughout the script.
Aaron
On 1/5/06, Mike Tuller <[EMAIL PROTECTED]> wrote:
>
> Excuse the last post, I didn't have all the code it there.
>
> I have a table listing items in a database, and have a delete button
> next to each item, and I want to be able to click on the delete and
> delete only that record in the database and then reload the page
> where it would display the updated information. Here is part of the
> code I have.
>
> // list elements one by one until there are no more in the
> database
> while ( $row=mysql_fetch_array($result2) )
> {
> if ($row[range] != "")
> {
> echo "
> <form action=".$_SERVER['PHP_SELF']."
> method=\"post\" name=
> \"deleteRange\">
> <tr class=\"trlist\">
> <td>$row[id]</td>
> <td>$row[range]</td>
> <td align=\"right\"><input type=\"submit\"
> name=\"deleteRange\"
> value=\"Delete\" /></td>
> </tr>
> </form>
> ";
> }
> }
> echo "</table>";
>
> echo "
> <br />
> <form action=".$_SERVER['PHP_SELF']." method=\"post\"
> name=
> \"addrange\">
> <table class=\"nolist\">
> <tr>
> <td>Add Range: $row[id]</td>
> <td><input type=\"text\"
> name=\"name\" size=\"53\" tabindex=\"9
> \" /></td>
> <td align=\"right\"><input
> type=\"submit\" name=\"addRange\"
> value=\"Add Range\" /></td>
> </tr>
>
> </table>
> </form>";
>
>
>
> }
> elseif (isset($_POST['deleteRange']))
> {
>
> $query = "delete from district.ip_range where id = $row[id]";
>
> mysql_query($query, $link) or die (mysql_error());
>
> echo "Record ".$row[id]." has beed deleted.";
>
> }
>
> They key I am using to find the record I want to delete is the the
> $row[id], but that is out of the scope of where the variable is set.
> Is there a way to set a variable so that it goes outside the scope?
>
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