Look into the MySQL YEAR() function to extract the year from a specific
date.
Start here:
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html




On 10/28/06, Beauford <[EMAIL PROTECTED]> wrote:

I posted this here as I figured I would need to manipulate this using PHP.
The code below doesn't quite work because the date is in the format of
05/05/2006. So I am getting totals for each date, not each year. I need
the
totals for each year, regardless of the day or month. This is why I
figured
I'd need to use PHP to maybe put it in an array first or something.

Thanks

-----Original Message-----
From: Joe Wollard [mailto:[EMAIL PROTECTED]
Sent: October 28, 2006 10:30 PM
To: Ed Lazor
Cc: Beauford; PHP
Subject: Re: [PHP] Query question

Agreed, this should go to a MySQL list. But in the spirit of helping I
think
the following should give you a good starting point.

SELECT `year`, COUNT(`year`) AS `count` FROM `tbl` GROUP BY `year` ASC


On 10/28/06, Ed Lazor <[EMAIL PROTECTED]> wrote:
>
> Use the mysql list :)
>
>
> On Oct 28, 2006, at 3:01 PM, Beauford wrote:
>
> > Hi,
> >
> > I have a MySQL database with a date field and a bunch of other
> > fields. The date field is in the format - 01/01/2006. What I want to
> > do is query the database and create a table that shows just the year
> > and how many instances of the year there is. I have been taxing my
> > brain for a simple solution, but just not getting it. Any
> > suggestions?
> >
> > Thanks
> >
> > Example output.
> >
> > Year  Count
> >
> > 2002  5
> > 2003  8
> > 2004  9
> > 2005  15
> > 2006  22
> >
> > ps - I get this information sent to me and I can't change any of the
> > data. I just enter it in the db and then hopefully do the query on
> > it.
> >
> >
>
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