Hello Diego,
You need to use copy()
If the form input is like this: file: <input name="userfile" type="file">
<input type="submit"
Then PHP will assign a few variables automatically to the file, which
include:
$file_name - actual name of the file (pic.jpg)
$file_size - size in bytes of the file
$file_type - MIME type of the file.
This:
<input type="hidden" name="MAX_FILE_SIZE" value="1000">Send this
Will only let you upload a file of less than 1kb if you program around that
(1024 bytes in a Kb). Setting to 102400 would give you a max upload size of
100 Kb.
So, simply:
<?
if ($file_size < $MAX_FILE_SIZE) {
@copy($file, "/path/to/dir/" . $file_name)
or die ("Something's up.");
} else {
echo "Sorry. Your file was bigger than the allowed size of " .
round(($MAX_FILE_SIZE / 1024), 2) ."Kb. Please go back and try again.";
}
?>
You can of course test whether the file being uploaded is a type you want,
like "image/jpeg" from the $file_type.
Hope this helps.
James.
"Diego Pérez Rández" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
>
> Hi to all:
>
> I don`t konw very well php. I do examples everyday and solve some
> problems. But in other i need help.
>
> Today i want to upload a file. I have the form that you can find in
> the php manual.
>
> <form enctype="multipart/form-data" action="_URL_" method="POST">
> <input type="hidden" name="MAX_FILE_SIZE" value="1000">Send this
> file: <input name="userfile" type="file"> <input type="submit"
> value="Send File">
> </form>
>
> My problem is that i don´t know how to programe the php program that
> upload the file. I do a lot of examples, but not work.
>
> Can someone give me help.
>
>
> Thanks.
>
>
> Best regards, Diego
>
>
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