This should work:
global.php
<?
function myFunc($file) { echo $file; }
?>
one.php
<?
include( 'global.php' );
echo 'You are in file: ';
myFunc(__FILE__);
?>
two.php
<?
include( 'global.php' );
echo 'You are in file: ';
myFunc(__FILE__);
?>
Christoph Boget wrote:
> Let's say I have the following 3 files
>
> global.php
> <?
> function myFunc() { echo __FILE__; }
> ?>
>
> one.php
> <?
> include( 'global.php' );
> echo 'You are in file: ';
> myFunc();
> ?>
>
> two.php
> <?
> include( 'global.php' );
> echo 'You are in file: ';
> myFunc();
> ?>
>
> In each case, what is echoed out for __FILE__ is global.php. Apart from
> analyzing the debug_backtrace array, is there any way that myFunc() would
> display "one.php" and "two.php" respectively?
>
> thnx,
> Christoph
>
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