global.php
<?php
function myFunc($file) {
echo $file;
}
?>
one.php
<?php
include( 'global.php' );
echo 'You are in file: ';
myFunc($file = __FILE__);
?>
might work..
Christoph Boget wrote:
Let's say I have the following 3 files
global.php
<?
function myFunc() { echo __FILE__; }
?>
one.php
<?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?>
two.php
<?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?>
In each case, what is echoed out for __FILE__ is global.php. Apart from
analyzing the debug_backtrace array, is there any way that myFunc() would
display "one.php" and "two.php" respectively?
thnx,
Christoph
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