Or, you could do...
$cat = 'butch';
${"rm_{$cat}_adt"} = 'is cool'; // This would set the variable $rm_butch_adt
equal to 'is cool'
-js
----- Original Message -----
From: "scott [gts]" <[EMAIL PROTECTED]>
To: "php" <[EMAIL PROTECTED]>
Sent: Wednesday, June 20, 2001 8:37 AM
Subject: RE: [PHP] inserting a variable into a variable
> you so totally could use an assoc. array right now:
>
> $cat_adt = "x";
> $rm = "y";
>
> $a[ $cat_adt ] = "whatever";
> $a[ "$rm"."$cat_adt" ] = "Yeah";
>
> print $a['yx'];
>
>
> save yourself a lot of trouble and dont bother with
> variables-of-variables and trying to get
> $rm_$cat_adt == $rm_x
>
> just use a hash... that's what it's there for ;)
>
>
> > -----Original Message-----
> > From: Tom Carter [mailto:[EMAIL PROTECTED]]
> > Sent: Wednesday, June 20, 2001 5:24 AM
> > To: Hasan Niyaz; [EMAIL PROTECTED]
> > Subject: Re: [PHP] inserting a variable into a variable
> >
> >
> > > I have come to a situation where i am having a variable inside
another
> > variable.
> > > for example.
> > >
> > > $rm_$cat_adt
> >
> > PHP would read this as trying to prepend the variable $cat_adt to the
> > variable $rm_
> >
> > You seem to be trying to insert the variable $cat into the middle of a
> > variable.. possible, but probably better to slightly rethink your naming
> > strategy
> >
> > HTH,
> > Tom
> >
> > >
> > > The above is a variable and $cat is again another variable
> > > This does not work..
> > >
> > > Need some help!
> > >
> > >
> > > Thanks,
> > > Hasan
> > >
> >
>
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