var_dump looks like this:
array(2) { [0]=> string(9) "wehost006" [1]=> string(2) "72" } array(2) {
[0]=> string(8) "H7848-49" [1]=> string(2) "71" } array(2) { [0]=> string(7)
"H7853-2" [1]=> string(2) "70" } array(2) { [0]=> string(7) "H7842-2" [1]=>
string(2) "64" } array(2) { [0]=> string(9) "WEHOST005" [1]=> string(2)
"64" } array(2) { [0]=> string(7) "h7835-2" [1]=> string(2) "57" } array(2)
{ [0]=> string(9) "wehost007" [1]=> string(2) "56" } array(2) { [0]=>
string(7) "H7814-1" [1]=> string(2) "55" } array(2) { [0]=> string(5)
"H0542" [1]=> string(2) "54" } array(2) { [0]=> string(8) "H7811-12" [1]=>
string(2) "54" }
""Dan Joseph"" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
On Wed, Sep 17, 2008 at 4:21 PM, Vinny Gullotta
<[EMAIL PROTECTED]>wrote:
var_dump($i); looks messy, but I can see the server names in there and
they
are the correct names.
"Micah Gersten" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
Do var_dump($i) in the loop to see if you're getting the data you want.
Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com
Vinny Gullotta wrote:
Still no luck displaying the stupid servername. Any other things I can
try?
"Micah Gersten" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
You'll want to change your Order By statement to 'ORDER BY CountSteps
DESC'.
Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com
Vinny Gullotta wrote:
echo $query;
yields
SELECT servername, COUNT(steps) as CountSteps FROM monitoring WHERE
steps = 'IISRESET' AND timestamp <= '2008-09-17 11:40:34' AND
timestamp >= '2008-08-17' GROUP BY servername ORDER BY COUNT(*) DESC
LIMIT 10
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Can you show us one of the var_dumps?
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www.canishosting.com - Plans start @ $1.99/month.
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