Try to echo the $target_url var. What's on it?
Try to echo the $args var. What's on it? How do you pass the $args? Zechim zechim.com São Paulo/Brazil -----Mensagem original----- De: Miller, Terion [mailto:tmil...@springfi.gannett.com] Enviada em: sexta-feira, 8 de maio de 2009 10:27 Para: Jônatas Zechim; Miller, Terion; PHP-General List Assunto: Re: RES: [PHP] CURL error help On 5/8/09 8:04 AM, "Jônatas Zechim" <zechim....@gmail.com> wrote: Try to change this: curl_setopt($ch,CURLOPT_URL,$targets); to: curl_setopt($ch,CURLOPT_URL, $target_url); Zechim zechim.com São Paulo/Brazil Thanks for the suggestion: Tried it and get this error now: Warning: file_get_contents($target_url) [function.file-get-contents]: failed to open stream: No such file or directory in /var/www/vhosts/getpublished.news-leader.com/httpdocs/Warrants/inc/dom.php on line 39 On line #39 from my dom.php file is this : // get html dom form file function file_get_html() { $dom = new simple_html_dom; $args = func_get_args(); $dom->load(call_user_func_array('file_get_contents', $args), true); return $dom; } I think somehow the array is not being read or it's trying to pass the full array of url's as one url? Therefore saying it does not exist? My best guess, am I making the array wrong?
