Hello everyone, Sorry for bothering you again. Today I met a problem exactly described by a developer in users' notes that follow the preg_replace description in the manual: info at gratisrijden dot nl 02-Oct-2009 02:48 if you are using the preg_replace with arrays, the replacements will apply as subject for the patterns later in the array. This means replaced values can be replaced again.
Example: <?php $text = 'We want to replace BOLD with the <boldtag> and OLDTAG with the <newtag>'; $patterns = array( '/BOLD/i', '/OLDTAG/i'); $replacements = array( '<boldtag>', '<newtag>'); echo preg_replace ($patterns, $replacements, $text); ?> Output: We want to replace <b<newtag>> with the <<b<newtag>>tag> and <newtag> with the <newtag> Look what happend with BOLD. Is there any solution to this besides any two-step sophisticated trick like case changing? Thanks! -- With best regards from Ukraine, Andre Http://oire.org/ - The Fantasy blogs of Oire Skype: Francophile; Wlm&MSN: arthaelon @ yandex.ru; Jabber: arthaelon @ jabber.org Yahoo! messenger: andre.polykanine; ICQ: 191749952 Twitter: http://twitter.com/m_elensule -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
