Andre Polykanine wrote:
> Hello everyone,
>
> Sorry for bothering you again.
> Today I met a problem exactly described by a developer in users' notes
> that follow the preg_replace description in the manual:
> info at gratisrijden dot nl
> 02-Oct-2009 02:48
> if you are using the preg_replace with arrays, the replacements will apply as
> subject for the patterns later in the array. This means replaced values can
> be replaced again.
>
> Example:
> <?php
> $text =
> 'We want to replace BOLD with the <boldtag> and OLDTAG with the <newtag>';
>
> $patterns
> = array(
> '/BOLD/i',
> '/OLDTAG/i');
> $replacements
> = array(
> '<boldtag>',
> '<newtag>');
>
> echo preg_replace
> ($patterns, $replacements, $text);
> ?>
>
> Output:
> We want to replace <b<newtag>> with the <<b<newtag>>tag> and <newtag> with
> the <newtag>
>
> Look what happend with BOLD.
>
> Is there any solution to this besides any two-step sophisticated trick
> like case changing?
> Thanks!
>
> --
> With best regards from Ukraine,
> Andre
> Http://oire.org/ - The Fantasy blogs of Oire
> Skype: Francophile; Wlm&MSN: arthaelon @ yandex.ru; Jabber: arthaelon @
> jabber.org
> Yahoo! messenger: andre.polykanine; ICQ: 191749952
> Twitter: http://twitter.com/m_elensule
>
>
Well, for the example you gave, why use regex? Check this out as an example.
<plaintext><?php
$text = 'We want to replace BOLD with the <boldtag> and OLDTAG with the
<newtag>';
$regex = array(
'/BOLD/i',
'/OLDTAG/i',
);
$oldtags = array(
'BOLD',
'OLDTAG',
);
$replacements = array(
'<boldtag>',
'<newtag>',
);
# Original String
echo $text."\n";
# After regex is applied
echo preg_replace($regex, $replacements, $text)."\n";
# After plain tag replacement happens
echo str_replace($oldtags, $replacements, $text)."\n";
?>
See if that works for you.
--
Jim Lucas
"Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them."
Twelfth Night, Act II, Scene V
by William Shakespeare
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