On 1 June 2010 16:33, Ashley Sheridan <a...@ashleysheridan.co.uk> wrote: > > On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote: > > $re1 = '/^[a-z]++$/i'; > $re2 = '/^[a-z ]++$/i'; > > > > -- > ----- > Richard Quadling > "Standing on the shoulders of some very clever giants!" > EE : http://www.experts-exchange.com/M_248814.html > EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp > Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731 > ZOPA : http://uk.zopa.com/member/RQuadling > > > Why the double ++ in the expressions there? Surely one + would match the 1 or > more characters that you need and the second one would just be surplus? > > Thanks, > Ash > http://www.ashleysheridan.co.uk > >
++ doesn't give back. As there is no need to do any backtracking, this is supposed to be a slight optimization. -- ----- Richard Quadling "Standing on the shoulders of some very clever giants!" EE : http://www.experts-exchange.com/M_248814.html EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731 ZOPA : http://uk.zopa.com/member/RQuadling -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
