On 1 June 2010 17:33, Ashley Sheridan <a...@ashleysheridan.co.uk> wrote: > On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote: > >> $re1 = '/^[a-z]++$/i'; >> $re2 = '/^[a-z ]++$/i'; >> >> >> >> -- >> ----- >> Richard Quadling >> "Standing on the shoulders of some very clever giants!" >> EE : http://www.experts-exchange.com/M_248814.html >> EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp >> Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731 >> ZOPA : http://uk.zopa.com/member/RQuadling >> > > > Why the double ++ in the expressions there? Surely one + would match the > 1 or more characters that you need and the second one would just be > surplus? >
Equally important: why have three people already done this persons homework. 5 minutes googling would have answered this ... -- <hype> WWW: http://plphp.dk / http://plind.dk LinkedIn: http://www.linkedin.com/in/plind BeWelcome/Couchsurfing: Fake51 Twitter: http://twitter.com/kafe15 </hype> -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
