Hi, i have a strange problem.
I get a users birthdate with three dropdown menus (year, month and day of month). I get these values into one string with: $user_birthdate = $birth_year . $birth_month . $birth_day; If i echo $user_birthdate after this it is correct (yyyymmdd). But when i insert the value of $user_birthdate into MySql it gets the value '8388607'. It doesn´t matter what value $user_birthdate had originally - it always inserts as 8388607. Any ideas??? The db question looks like this btw: $query = "INSERT INTO users "; $query .= "(user_name, user_birthdate, user_city, user_mail, user_icq, user_msn, user_www, user_login, user_password) "; $query .= " values('$user_name', '$user_birthdate', '$user_city', '$user_mail', '$user_icq', '$user_msn', '$user_www', '$user_login', '$user_password')"; Regards # Daniel Alsén | www.mindbash.com # # [EMAIL PROTECTED] | +46 704 86 14 92 # # ICQ: 63006462 | +46 8 694 82 22 # # PGP: http://www.mindbash.com/pgp/ # -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]