Hola Daniel: Te escribo en castellano ya que veo que el ingl�s no es tu idioma natural.
Creo que el error se produce al concatenar las variables, acordate que para indicar que las variables con cadenas ten�s que encerrarlas entre "", yo lo definir�a as�: $user_birthdate = "$birth_year-$birth_month-$birth_day"; // 1982-12-08 Saludos Edgardo "Daniel als�n" <[EMAIL PROTECTED]> escribi� en el mensaje [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > Hi, > > i have a strange problem. > > I get a users birthdate with three dropdown menus (year, month and day of > month). I get these values into one string with: > > $user_birthdate = $birth_year . $birth_month . $birth_day; > > If i echo $user_birthdate after this it is correct (yyyymmdd). But when i > insert the value of $user_birthdate into MySql it gets the value '8388607'. > It doesn�t matter what value $user_birthdate had originally - it always > inserts as 8388607. > > Any ideas??? > > > > The db question looks like this btw: > > $query = "INSERT INTO users "; > > $query .= "(user_name, user_birthdate, user_city, user_mail, user_icq, > user_msn, user_www, user_login, user_password) "; > > $query .= " values('$user_name', '$user_birthdate', '$user_city', > '$user_mail', '$user_icq', '$user_msn', '$user_www', '$user_login', > '$user_password')"; > > > Regards > # Daniel Als�n | www.mindbash.com # > # [EMAIL PROTECTED] | +46 704 86 14 92 # > # ICQ: 63006462 | +46 8 694 82 22 # > # PGP: http://www.mindbash.com/pgp/ # > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
