I tried that and strangely it didn't work and using eval() was really my only solution :( People told me to od $foo[$bar], $foo['$bar'], $foo["$bar"], $foo[($bar)], and the manual doesn't seem to mind $foo[$bar], but I dunno. It just wasn't working, and I was angry and depressed that I wasn't getting paid enough for what I was doing so I took the easy way out. It's the only time I ever used eval() in PHP.
> -----Original Message----- > From: Rasmus Lerdorf [mailto:[EMAIL PROTECTED]] > Sent: January 20, 2002 11:22 PM > To: Alex Dowgailenko > Cc: [EMAIL PROTECTED] > Subject: RE: [PHP] Re: eval() > > > > while (list($opid, $ppid, $amount, $pname) = > mysql_fetch_row($res)) { > > $eval = '$temp["'.$pname.'"] = $temp["'.$pname.'"] > + '.$amount.';'; > > eval($eval); > > $i++; > > Whoa... Why not simply: > > $temp[$pname] += $amount; > > ?? > > -Rasmus > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
