This isn't exactly what you want, but it is close: list($user_id,$field2,$field3,$field4) = $row;
where $row was retrieved via mysql_fetch_array() Just list each of the variable names in the list() function; include ALL fields' names included in $row -----Original Message----- From: Baloo :0) [mailto:[EMAIL PROTECTED]] Sent: Tuesday, February 19, 2002 3:41 PM To: [EMAIL PROTECTED] Subject: [PHP] explode? (table field to a variable of same name) How can I assign automatically all fields of a database to a variable of the same name? Instead of having to manually do $user_id=$row["user_id"]; etc Then how could I know the number of fields in the table so I can do a loop to print them all in html? In advance, thanks for your help. Alfredo -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
