you can't use a variable as a parameter for the included file... because
include does nothing else then putting the text of the include file on the
place of the include statement...
so this should work:
$var = 'bladibla';
include('index.php');
Greets,
Edward
----- Original Message -----
From: "Phil Schwarzmann" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, March 14, 2002 10:20 PM
Subject: [PHP] include() question
> Why doesn't this work...
>
> include("index.php?var='$var');
>
> I want to include a page in my code and send a variable to it but I get
> some funky error.
>
> THANKS!!
>
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