Nope, that code makes no sense. $_POST is an array containing the POST
variables. You make a copy of that array an put it in $foo thereby
overwriting the passed in $foo. Then you return $$foo which actually ends
up returning a variable named $Array. It does not look like you have a
$Array variable in scope, and it is surely not what the misguided coder
behind this code was trying to achieve. In short, this is completely
bogus.
-Rasmus
On Sun, 31 Mar 2002, Gary wrote:
> Can someone explain to me the reason for using return.
>
> function _getValue($foo)
> {
> $foo = $_POST;
> return ${$foo};
> }
>
> TIA
> Gary
>
>
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