would that work?

isn't $i++; abbr. for $i = $i + 1;

so now the $i + 20; doens't declare anything.

just like $i += $b; is abbr. $i = $i + $b;

Jule.


On Friday 17 May 2002 23:14, you wrote:
> Hmm... Wouldnąt you just do this?:
>
> for ($i=1; $i<=$num_pages; $i+20) {
>   // print stuff here
> }
>
> Rick
>
> "The vision must be followed by the venture. It is not enough to stare up
> the steps - we must step up the stairs." - Vance Havner
>
> > From: "Jason Soza" <[EMAIL PROTECTED]>
> > Date: Fri, 17 May 2002 19:19:28 -0800
> > To: <[EMAIL PROTECTED]>
> > Subject: [PHP] Feelin' dumb...
> >
> > Okay, I'm apologizing right now for this, but I hope it's at least
> > tolerable. I have this:
> >
> > for ($i=1; $i<=$num_pages; $i++) {
> > // print stuff here
> > }
> >
> > For each loop, I want to add 20 to $i, so after the first iteration, I
> > have 21, then 41, 61, etc. I've tried $i+20, $i + 20, I've tried looking
> > in the manual, but I assume this is some C-type function, and I'm not
> > familiar with C!
> >
> > Any helpers?
> >
> > Jason Soza
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php

-- 
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|   Jule Slootbeek               |
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