use single quotes: double quotes would confuse php with variable names.
it thinks that $General is a variable and replace it by it's empty content.
single quotes prevent php from evaluating the string:
$test_string = '1.2$General/ms1.zip';
single quotes on regex too (same reason). the backslash in this case
(\$) refers to perl regular expression syntax but does not take care of php !
$new_string = preg_replace('/\$/', "%", $test_string);
ub
At 10:58 29.06.02 -0400, Beverly Steiner wrote:
>I've tried everything I can think of to change a dallar sign in a string to
>something else or to split the string on the $ but I can't the the
>information that comes after the $.
>
>Typical string contains: 1.2$General/ms1.zip
>
>when I try:
> $new_string = preg_replace("/\$/", "%", $test_string);
>
>or (trying to avoid specifying the $):
> $new_string = preg_replace("/(\d\.\d{1,2})\D(\w.*$)/", "\1%\2",
>$test_string);
>
>echo "new_string is $new_string"; prints new_string is 1.2
>
>Has anyone solved this problem?
>
>Thanx,
>
>Bev
>
>
>--
>PHP General Mailing List (http://www.php.net/)
>To unsubscribe, visit: http://www.php.net/unsub.php
--
-----------------------------------------------
Ulrich Borchers
Brandenberger Stra�e 18, 41065 M�nchengladbach
fon +49-2161-175883
icq 1282868
-----------------------------------------------
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
