OK, this works.. This is wonderful.. But I don't get it.. I assigned two
separate variables to that array function.. I don't understand why this
works now, but thanks a lot for the help.
I hope I don't inadvertently run into this again...
-steve
$sql2 = mysql_connect("localhost", "eweb", "dbfun")
or die("Could not connect using default username and password LINE
14 <BR>");
mysql_select_db("actionregs", $sql2);
$top_level = mysql_query("SELECT * FROM williams", $sql2)
or die("Could not do query sql1 to find username. Link might not
have been made. What's up? LINE 19 <BR>");
// $sql2_results = mysql_fetch_array($top_level);
$query_sql2_rows = mysql_num_rows($top_level);
$rows = 0;
echo $query_sql2_rows;
print "<table style=\"font-family:Verdana; font-size:10pt\" border=0
cellpadding=4 width=90%>";
print "<tr bgcolor=\"#c0c0c0\"><th width=50>Action ID</th><th
width=100>Owner</th><th width=250>Technology</th><th>Summary</th></tr>";
for ($counter=0; $counter < $query_sql2_rows; $counter++) {
$tabledata = mysql_fetch_array($top_level);
echo "<td>$tabledata[0]</td>";
echo "<td>$tabledata[6]</td>";
echo "<td>$tabledata[2]</td>";
echo "<td>$tabledata[3]</td>";
echo "</tr>";
}
print "</table>";
-----Original Message-----
From: Brad Bonkoski [mailto:[EMAIL PROTECTED]]
Sent: Friday, September 06, 2002 3:34 PM
To: Steve Gaas
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] MySQL and Array's REALLY simple question but I'm not
GETTING it .. Ugh..
Well, when you run the command:
$sql2_results = mysql_fetch_array($top_level);
The first time, it automatically increments the result...
so you fetch the data bu do nothing with it...
so when you get to your loop, you are already at the second entry in
your database..
So, remove the first instance of that and see how it works..
HTH
-Brad
Steve Gaas wrote:
>Can anyone tell me what's wrong with my code? All I get output from this
is
>the LAST row of data from my Database. There are 2 rows, how do I make it
>pull data from all of the rows? It's not going through the loop like it
>should.... I need to be able to tell the mysql_fetch_array which row I
want
>in each it iteration of the for loop. The For loop increments counter, but
>there is no syntax to add $counter to the result_type. The same goes with
>fetch_row...
>
>What am I forgetting!!?? I know it's something simple
>
>
>*******
>
>$sql2 = mysql_connect("localhost", "eweb", "dbfun")
> or die("Could not connect <BR>");
>
>mysql_select_db("actionregs", $sql2);
>
>$top_level = mysql_query("SELECT * FROM williams", $sql2)
> or die("Could not do query <BR>");
>
>$sql2_results = mysql_fetch_array($top_level);
>$query_sql2_rows = mysql_num_rows($top_level);
>
>echo $query_sql2_rows;
>// echo's 2 rows
>
>print "<table style=\"font-family:Verdana; font-size:10pt\" border=0
>cellpadding=4 width=90%>";
>
>print "<tr bgcolor=\"#c0c0c0\"><th width=50>Action ID</th><th
>width=100>Owner</th><th width=250>Technology</th><th>Summary</th></tr>";
>
>for ($counter=0; $counter < $query_sql2_rows; $counter++) {
> $tabledata = mysql_fetch_array($top_level);
> echo "<td>$tabledata[0]</td>";
> echo "<td>$tabledata[6]</td>";
> echo "<td>$tabledata[2]</td>";
> echo "<td>$tabledata[3]</td>";
> echo "</tr>";
> }
>print "</table>";
>
>Thanks.
>
>
>
>
>
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