sorry - seems my earlier post was base64 - apologies to all :-( - here it is
again


yes - am using 4.2.1

output from phpinfo() shows:

_SERVER["argv"] Array
(
)

_SERVER["argc"] 0

which agrees with the $argc and $argv output.

details on the build include:

Build Date Jul 18 2002 08:29:02
Configure Command './configure' '--prefix=/usr/local/php'
'--with-config-file-path=/usr/local/bin/' '--enable-ftp' '--without-gd'
'--with-mysql'
Server API CGI

the php.ini shows register_globals on and register_argc_argv on

works fine if I call the php mod directly from the command line - and parses
the passed variable fine - just doesnt do it when called using the tick (or
system function) from Perl


Jim Carey
www.OZbcoz.com discount domain registration



> -----Original Message-----
> From: Sascha Cunz [mailto:[EMAIL PROTECTED]]
> Sent: Friday, 11 October 2002 9:28 AM
> To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
> Subject: Re: [PHP] Calling PHP (cgi) from a perl script and passsing
> parameters
>
>
> What you're referring is CLI, not CGI Version of PHP.
>
> Anyway, i assume, you're using a PHP version 4.2 or higher.
> Have a look at the $_SERVER['argc'] and $_SERVER['argv'].
>
> Sascha
>
> Am Donnerstag, 10. Oktober 2002 23:57 schrieb Jim Carey:
> > Hi,
> >
> > have been having problems passing parameters to a PHP script from a Perl
> > script . I call the PHP script using (as an example):
>
> > $a=`/home/ozbcoz/http/testphp.php fred=testing`;
> > print "$a";
> >
> >
> > then I have a PHP script showing:
> >
> > #!/usr/local/php/bin/php -q
> > <?
> >
> > print "count=$argc<br>";
> > print "0=$argv[0]<br>";
> > print "1=$argv[1]<br>";
> > print "2=$argv[2]<br>";
> > phpinfo();
> > ?>
> >
> > the outout comes out as:
> >
> > count=0
> > 0=
> > 1=
> > 2=
> > plus the phpinfo bumpf - which shows argc as 0 and an empty
> array for argv
> >
> > sny clues anyone ?
> >
> > Jim Carey
> > www.OZbcoz.com discount domain registration
> >
>
>
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