Why? echo "THE VARIABLE ".(please help me right here)." EQUALS ".$tigidizougou;
Obviously the variables name is tigidizougou, so just do this: echo "THE VARIABLE tigidizougou EQUALS ".$tigidizougou; Or am I missing something here? > Theoriquement it is not possible, because you cannot use any variable since > you don't know its name- > > But you can cope something with get_defined_vars() in which you set every > variable without distinction into an array- and after you select the > variable you need using some criterias. > > like this > $array = get_defined_vars() ; > foreach ($array as $key=>$value) > if (ereg("EREG_CRITERIA",$key)) echo "La variable $KEY est egale a $value" > ; > > Elsewhere if you know the name of the variable you would like to use > do simply like this: > > $tigidizougou = 12; > echo "THE VARIABLE tigidizougou EQUALS ".$tigidizougou; > > > ----- Original Message ----- > From: "franck raynal" <[EMAIL PROTECTED]> > To: "php-general" <[EMAIL PROTECTED]> > Sent: Friday, November 01, 2002 9:09 AM > Subject: [PHP] How printing the name and value of a variable ? > > > Hello, > I'd like to print the name of a variable, in order to get something like > this : > > THE VARIABLE tigidizougou EQUALS 12 ! > > from the original code below : > > $tigidizougou = 12; > echo "THE VARIABLE ".(please help me right here)." EQUALS ".$tigidizougou; > > Any idea ? Thanks you. > > Franck > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php