[PHP] Using fopen() to open a php file with variables.

[Jay \(PHP List\)]

Okay, I need to retrieve the output of a php file with variables being
passed to it.  Example:

$calendar_file = "make_calendar.php3?month=$month&year=$year";
$fp = $fp = fopen("$calendar_file", "r");
while (!feof ($fp)) {
        $buffer = fgets($fp, 4096);
        $calendar_html .= $buffer;
}
fclose($fp);

It gives me an error that the file doesn't exist, but it does.  Any
suggestions?

Jay Douglas
Systems Consultant
Fort Collins, CO