Why don't you just use include?
$month = 12;
$year = 2002;
// This include has access to the above variables
include 'make_calendar.php3';
Include it wherever you intended to print $caledar_html.
It doesn't exist in your code because the url is seen as
part of the filename.
Regards,
Philip Olson
On Wed, 11 Dec 2002, Jay (PHP List) wrote:
> Okay, I need to retrieve the output of a php file with variables being
> passed to it. Example:
>
> $calendar_file = "make_calendar.php3?month=$month&year=$year";
> $fp = $fp = fopen("$calendar_file", "r");
> while (!feof ($fp)) {
> $buffer = fgets($fp, 4096);
> $calendar_html .= $buffer;
> }
> fclose($fp);
>
> It gives me an error that the file doesn't exist, but it does. Any
> suggestions?
>
> Jay Douglas
> Systems Consultant
> Fort Collins, CO
>
>
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