the function with the same name as the class is the constructor and is called when the instance is created. So "$first = new first" runs first::first() without passing any parameters hence the warning.
Tim Ward http://www.chessish.com mailto:[EMAIL PROTECTED] ----- Original Message ----- From: Chris Hayes <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Monday, February 03, 2003 7:35 PM Subject: Re: [PHP] Help with classes (oop) > Apparently it does not like the function name to be the same as the class > name. So change one of them. > > ><? php; > >class first > >{ > > var $age; > > var $name; > > > > function first($age, $name) > > { > > return $age.$name; > > } > >} > > > >//main script > >$first = new first; > >$test=$first->first(35, "chris"); > > > >print $test; > ?> > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
